Solution

Simplify the following. $$\log_5 (3-2)$$




$$\begin{array}{rcll} \log_5 (3-2) &=& \log_5 1 & \scriptsize{\textrm{by simple arithmetic}}\\\\ &=& 0 & \scriptsize{\textrm{recalling that } 5^0 = 1} \end{array}$$